How to Format JSON in Java
Feb 01, 2026 3 min read
Java does not have a built-in JSON formatter, but the two most popular libraries, Jackson and Gson, both provide very easy ways to parse and pretty-print JSON data.
Example Code
Java
// Using Jackson (FasterXML)
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.JsonNode;
public class JsonFormatter {
public static void main(String[] args) throws Exception {
String jsonString = "{\"name\":\"John\",\"age\":30,\"city\":\"New York\"}";
ObjectMapper mapper = new ObjectMapper();
// Parse the JSON string
Object jsonObject = mapper.readValue(jsonString, Object.class);
// Pretty print it
String formattedJson = mapper.writerWithDefaultPrettyPrinter()
.writeValueAsString(jsonObject);
System.out.println(formattedJson);
}
} Common Use Cases
- Returning readable REST API JSON responses in frameworks like Spring Boot
- Formatting and writing JSON to log files
- Debugging deep, complex nested DTO objects
💡 Pro Tips for Java
- Jackson
writerWithDefaultPrettyPrinter()formats with spaces by default. - With Jackson, you can also inject
ObjectWriterinto Spring controllers. - Gson is lightweight, but Jackson offers better performance for large JSON datasets.
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